WebDetermine whether the series X∞ k=1 k(k +2) (k +3)2 is convergent or divergent. If it is convergent, find its sum. Answer: This series diverges. To see this, I will show that the terms in the sequence do not go to zero: lim k→∞ k(k +2) (k +3)2 = lim k→∞ k2 +2k k2 +6k +9. Dividing numerator and denominator by k2 yields lim k→∞ 1 ... WebDetermine whether the series converges or diverges. ∑∞ k=1 k sin^2 k / 1+k^3. ... Test the series for convergence or divergence. ∑∞ k=1 k ln k / (k+1)^3. calculus. A patient takes 150 mg of a drug at the same time every day. Just before each tablet is taken, 5% of the drug remains in the body. What quantity of the drug is in the body ...
Find out the answer to "a. Find an upper bound for the remainder ...
WebStart your trial now! First week only $4.99! arrow_forward Literature guides Concept explainers Writing guide Popular textbooks Popular high school textbooks Popular Q&A Business Accounting Business Law Economics Finance Leadership Management Marketing Operations Management Engineering AI and Machine Learning Bioengineering Chemical … WebFollowing Ramanujan’s work on modular equations and approximations of π, there are formulas for 1 / π of the form. ∑ k = 0 ∞ ( 1 2 ) k ( 1 d ) k ( d − 1 d ) k k ! 3 ( a k + 1 ) ( λ d … the hangar restaurant st pete fl
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Webk= X∞ n=k+1 1 n3 to be less than 0.05 =1 20 Now, the remainder estimate for the integral test says that Z∞ k+1 1 x3 dx ≤ R k≤ Z∞ k 1 x3 dx, so we know that R k<1 20whenever the integral on the right is less than20 In other words, we want 1 20 > Z∞ k 1 x3 dx = − 1 2x2 = 1 2k2 Now,1 2k2<20whenever 20 < 2k 2or, equivalently, when 10 < k2. WebX∞ k=0 (−1)kxk for x < 1 Integration: ln(1+x) = X∞ k=0 (−1)k k +1 xk+1(+C = 0) = X∞ k=1 (−1)k k xk = x− 1 2 x2 + 1 3 x3 − 1 4 x4 +··· The interval of convergence is (−1,1]. At x = … WebEvaluate the sum, ∑_ (k=1)^n 〖1/ (k (k+1) (k+2)……… (k+r)) 〗 742 views Jul 3, 2024 Evaluate the sum, ∑_ (k=1)^n 〖1/ (k (k+1) (k+2)……… (k+r)) 〗 Full Playlist Sequence and... the battery experts